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Quantitative Aptitudeमात्रात्मक योग्यता · दौड़ और खेल

Races and Gamesदौड़ और खेल questions and answersप्रश्न और उत्तर

Race questions are time-and-distance questions in disguise. Every statement about a margin or a start is really a statement about how far two runners get in the same time, and that fixes the ratio of their speeds.

  • Unlimitedअसीमित fresh questionsनए प्रश्न
  • Answersउत्तर always one tap awayहमेशा एक टैप दूर
  • 1 subtopicउप-टॉपिक

Practice questions are in English for now.अभ्यास के प्रश्न अभी अंग्रेज़ी में हैं।

How races and games worksदौड़ और खेल को समझिए

“A beats B by 20 m in a 100 m race” means that when A crosses the line after 100 m, B has run 80 m. They ran for the same time, so their speeds are in the ratio 100 : 80 = 5 : 4. “A can give B a start of 20 m” in a dead heat says exactly the same thing.

“A beats B by 20 m or by 4 seconds” adds a second fact: B needs 4 more seconds to run the last 20 m. That gives B’s speed (5 m/s), then B’s time for the whole race, and A’s time is 4 seconds less.

With three runners, chain the distances, never the margins. If A beats B by 20 m and B beats C by 10 m in 100 m races, then when A finishes, B has run 80 m and C has run 80 × 90/100 = 72 m, so A wins by 28 m, not 30 m.

Tricks that save timeसमय बचाने वाली ट्रिक्स

All tricks →सभी ट्रिक्स →

Each trick says when to use it, why it works and when it fails. Formula tricks are checked by code over their whole range.हर ट्रिक बताती है कि उसे कब इस्तेमाल करें, वह क्यों काम करती है और कब नहीं। सूत्र वाली ट्रिक्स को कोड से उनकी पूरी रेंज पर जाँचा गया है।

Formulaसूत्रRarely taughtकम सिखाई जाने वाली✓ Checked on 2,500 cases✓ 2,500 मामलों पर जाँची गई

Three runners: x + y − xy/L, not x + y

Use it when:कब इस्तेमाल करें: A beats B by x m and B beats C by y m in races of the same length L; how much does A beat C by?

  1. Add the two margins.
  2. Subtract their product divided by the race length: margin = x + y − xy/L.
Exampleउदाहरण

In a 200 m race A beats B by 20 m and B beats C by 10 m. By how much does A beat C?

→ 20 + 10 − 200/200 = 29 m

Why it works, and when it failsयह क्यों काम करती है, और कब नहीं

Why:क्यों: When A finishes, B has run L − x and C has run (L − x)(L − y)/L. So A wins by L − (L − x)(L − y)/L = x + y − xy/L. It is the successive-discount formula a + b − ab/100 with L in place of 100.

Limits:सीमाएँ: Both margins must be over the same race length L, and runners must keep steady speeds. Convert “by t seconds” margins to metres first.

Formulaसूत्र✓ Checked on 1,200 cases✓ 1,200 मामलों पर जाँची गई

“Beats by x m or t seconds”: winner’s time = t(L − x)/x

Use it when:कब इस्तेमाल करें: A race question says the winner beats the loser by a distance or by a time, and asks for a runner’s time.

  1. The loser runs the last x m in t seconds, so the loser’s whole race takes L × t/x.
  2. The winner is t seconds faster: winner’s time = t(L − x)/x.
Exampleउदाहरण

In a 1,000 m race A beats B by 50 m or 10 s. A’s time?

→ 10 × 950/50 = 190 s (B takes 200 s)

Why it works, and when it failsयह क्यों काम करती है, और कब नहीं

Why:क्यों: B’s speed is x/t, so B needs L/(x/t) = Lt/x seconds for the race. A finishes t seconds earlier: Lt/x − t = t(L − x)/x.

Limits:सीमाएँ: Needs steady speeds. The x metres and t seconds must describe the same margin, measured when the winner finishes.

Solved examplesहल किए गए उदाहरण

Answers and full solutions are shown. Hide them to test yourself first.उत्तर और पूरे हल दिखाए गए हैं। पहले खुद को परखने के लिए इन्हें छिपाइए।

  1. Example 1उदाहरण 1 · Races: beating, giving a start and dead heats · Easyआसान

    In a 200 m race, Lakshmi can give Fatima a start of 2 m and the race ends in a dead heat. What is the ratio of Lakshmi’s speed to Fatima’s speed?

    1. 100 : 1
    2. 99 : 100
    3. 101 : 100
    4. 100 : 99
    Answer:उत्तर: 100 : 99
    1. In the time Lakshmi runs 200 m, Fatima runs 198 m.
    2. Same time, so speed ratio = distance ratio = 200 : 198.
    3. In lowest terms: 100 : 99.
  2. Example 2उदाहरण 2 · Races: beating, giving a start and dead heats · Mediumमध्यम

    In a 100 m race, Harpreet beats Aarav by 8 m or by 1 seconds. How long does Harpreet take to run the 100 m?

    1. 12.5 seconds
    2. 11.5 seconds
    3. 0.09 seconds
    4. 13.5 seconds
    Answer:उत्तर: 11.5 seconds
    1. Aarav runs 8 m in 1 s, so Aarav’s speed = 8 m/s.
    2. Aarav’s time for 100 m = 100/8 = 12.5 s.
    3. Harpreet finishes 1 s earlier: 12.5 − 1 = 11.5 s.
  3. Example 3उदाहरण 3 · Races: beating, giving a start and dead heats · Hardकठिन

    In a 200 m race, Fatima can give Ananya a start of 10 m and Aditya a start of 48 m. How much start can Ananya give Aditya in a 200 m race?

    1. 40 m
    2. 160 m
    3. 38 m
    4. 50 m
    Answer:उत्तर: 40 m
    1. In the same time, Ananya runs 190 m and Aditya runs 152 m.
    2. When Ananya runs 200 m, Aditya runs 200 × 152/190 = 160 m.
    3. So Ananya can give Aditya a start of 200 − 160 = 40 m.
  4. Example 4उदाहरण 4 · Races: beating, giving a start and dead heats · Mediumमध्यम

    Meera and Fatima run at speeds in the ratio 5 : 4. In a 400 m race, how much start should Meera give Fatima so that the race ends in a dead heat?

    1. 320 m
    2. 80 m
    3. 44.44 m
    4. 100 m
    Answer:उत्तर: 80 m
    1. In the time Meera runs 400 m, Fatima runs 400 × 4/5 = 320 m.
    2. So Fatima must start 400 − 320 = 80 m ahead.
  5. Example 5उदाहरण 5 · Races: beating, giving a start and dead heats · Mediumमध्यम

    Ananya runs 10/9 times as fast as Aarav. In a 1000 m race, how much start should Ananya give Aarav so that the race ends in a dead heat?

    1. 900 m
    2. 100 m
    3. 52.63 m
    4. 111.11 m
    Answer:उत्तर: 100 m
    1. In the time Ananya runs 1000 m, Aarav runs 1000 × 9/10 = 900 m.
    2. So Aarav must start 1000 − 900 = 100 m ahead.
  6. Example 6उदाहरण 6 · Races: beating, giving a start and dead heats · Mediumमध्यम

    In a 1000 m race, Rohan beats Tenzin by 310 m or by 31 seconds. How long does Rohan take to run the 1000 m?

    1. 131 seconds
    2. 69 seconds
    3. 100 seconds
    4. 13.93 seconds
    Answer:उत्तर: 69 seconds
    1. Tenzin runs 310 m in 31 s, so Tenzin’s speed = 10 m/s.
    2. Tenzin’s time for 1000 m = 1000/10 = 100 s.
    3. Rohan finishes 31 s earlier: 100 − 31 = 69 s.

Common mistakesआम गलतियाँ

  • Adding the two margins in a three-runner race; the second margin applies to a shorter distance.
  • Comparing the race length with the margin (100 : 20) instead of with the loser’s distance (100 : 80).
  • Using the winner’s speed where the question is about the loser, for example in “beats by x m or t seconds”.

Frequently asked questionsअक्सर पूछे जाने वाले प्रश्न

What does “A gives B a start of 10 m” mean?

B starts 10 m ahead of the line, so B runs 10 m less than A. If the race still ends in a dead heat, A runs L m in the time B runs L − 10 m.

How do I find by how much A beats C?

Find how far C has run when A finishes: multiply the fractions (L − x)/L and (L − y)/L by L. The margin is L minus that distance, which works out to x + y − xy/L.

Does the margin stay the same if the race is longer?

No. With unchanged speeds the margin is a fixed fraction of the race, so a 10 m margin in a 100 m race becomes 40 m in a 400 m race.

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