Example 1 · level 1
Evaluate lim (x → −2) (x³ + 2x² + 2x + 4).
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- Substituting x = −2 gives 0.
Answer: 0
For a polynomial, substitute directly. If substitution gives 0/0, factorise and cancel the common factor, or use lim (xⁿ − aⁿ)/(x − a) = naⁿ⁻¹.
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Evaluate lim (x → −2) (x³ + 2x² + 2x + 4).
Answer: 0
Evaluate lim (x → 5) (x² − 8x + 15)/(x − 5).
Answer: 2
Evaluate lim (x → 3) (x² − 9)/(x⁴ − 81).
Answer: 1/18