CLASS 9 SCIENCE · SOUND

Echo: distance of a reflecting surface

An echo travels to the surface and back, so 2d = v × t, i.e. d = vt/2. To hear a distinct echo the sound must return after at least 0.1 s.

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Worked examples

Example 1 · level 1

A child shouts near a cliff in the Western Ghats and hears the echo after 0.5 s. If sound travels at 346 m/s, how far (in m) is the cliff?

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  1. 2d = 346 × 0.5 = 173 m.
  2. d = 86.5 m.

Answer: 86.5 m

Example 2 · level 2

A ship's SONAR sends a pulse that returns from the seabed after 6 s. Speed of sound in sea water is 1500 m/s. Find the depth of the sea (in m).

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  1. 2d = 1500 × 6 = 9000 m
  2. d = 4500 m.

Answer: 4,500 m

Example 3 · level 3

Sound persists in our ear for about 0.1 s. If the speed of sound is 344 m/s, find the minimum distance (in m) of a wall for a distinct echo (correct to 2 decimal places).

Show solution
  1. 2d = 344 × 0.1 = 34.4 m
  2. d = 17.2 m.

Answer: 17.2 m

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