Example 1 · level 1
Arjun deposits ₹3,000 at the end of every year for 2 years in a recurring scheme earning 10% p.a. compounded annually. Find the future value of this annuity (nearest rupee).
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- i = 0.1, n = 2, A = ₹3,000.
- (1 + i)^2 = 1.21.
- FV = 3,000 × (1.21 − 1) ÷ 0.1 = ₹6,300.
Answer: ₹6,300