Example 1 · level 1
An object is placed 35 cm from a convex lens of focal length 10 cm. Find the image distance v in cm, with sign. Use the New Cartesian sign convention (distances measured from the pole/optical centre; along the incident light positive).
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- 1/v = 1/f + 1/u = 1/(+10) + 1/(−35)
- v = uf/(u + f) = +14 cm.
- Positive v: real image on the other side of the lens.
Answer: 14 cm