Example 1 · level 1
A current of 2 A flows through a 5 Ω heater coil for 30 s. Find the heat produced (in J).
Show solution
- H = 2² × 5 × 30 = 600 J.
Answer: 600 J
Heat produced H = I²Rt (joule). Doubling the current makes the heat four times.
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A current of 2 A flows through a 5 Ω heater coil for 30 s. Find the heat produced (in J).
Answer: 600 J
A 50 Ω resistor is connected across 50 V for 30 s. Find the heat produced (in J).
Answer: 1,500 J
A coil produces 19,200 J of heat in 120 s when a current of 2 A passes through it. Find its resistance (in ohm).
Answer: 40 ohm